Answer:
See explanation and image attached
Explanation:
Let us consider the mechanism attached to this answer. This is only one of the ways of synthesizing the required product.
The starting material is acetylene. This is reacted with sodamide in ammonia alongside methyl iodide. The process is repeated again, this time using butyl iodide. The alkyne is now reduced using hydrogen.
The alkane formed may now be chlorinated in the presence of light using the chlorine molecule. A mixture of alkyl halides are obtained.
