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A flying squirrel jumped from a tree 11 feet in the air at the initial velocity of 9 ft./s the equation H equals negative 2T squared +90+11 models his jump wear eight height iand T is time in seconds

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Answer:

The squirrel maximum height (h) = 21.125 ft

Step-by-step explanation:

The objective of this question is to determine the squirrel's maximum height.

Given that:

h = -2t² + 9t + 11

Differentiating h with respect to t, we get;

[tex]\dfrac{dh}{dt}= -4t +9[/tex]

At the time dh/dt = 0, the velocity is maximum

Thus;

-4t = -9

4t = 9

t = 9/4

t = 2.25 seconds

From;

h = -2t² + 9t + 11

h = - 2(2.25)² + 9(2.25) + 11

h = - 10.125 + 20.25 + 11

h = 21.125 ft

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