secondary alcohol (X) reacts with PCL5 to give alkyl halide (Y) which on dehydrohalogenation yield an alkene(Z).The alkene upon ozonolysis gives the mixture of ethanal and methanal.Identify X ,Y ,Z

Secondary alcohol is an alcohol in which the carbon that the functional group (OH group) is attached to is also attached to two alkyl group. Examples are 2-propanol and 2-butanol.

The secondary alcohol referred to in the question here is 2-propanol and it reacts with PCl₅ as seen below

H₃C-CH-CH₃ + PCl₅ ⇒ H₃C-CH-CH₃ + HCl + POCl₃

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OH Cl

The alkylhalide produced there is 2-chloropropane. Thus, we can see that X is 2-propanol and Y is 2-chloropropane.

When this 2-chloropropane undergoes dehydrohalogenation (removal of hydrogen and halogen) an alkene is formed. The reaction is seen below

H₃C-CH-CH₃ (-HCl) ⇒ H₃C-CH=CH₂

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Cl

The alkene produced (as seen above) is propene.

Confirmation: When propene undergoes ozonolysis, the compounds produced are ethanal and methanal as seen in the equation below

O

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H₃C-CH=CH₂ + O₃ ⇒ H₃C - CH CH₂ [-O] ⇒ CH + CH₂

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O O O O

The final products as seen above are methanal and ethanal

secondary alcohol (X) reacts with PCL5 to give alkyl halide (Y) which on dehydrohalogenation yield an alkene(Z).The alkene upon ozonolysis gives the mixture of ethanal and methanal.Identify X ,Y ,Z​

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secondary alcohol (X) reacts with PCL5 to give alkyl halide (Y) which on dehydrohalogenation yield an alkene(Z).The alkene upon ozonolysis gives the mixture of ethanal and methanal.Identify X ,Y ,Z