What is the magnitude of the instantaneous velocity (speed) of a freely falling object 13 s after it is released from a position of rest? Consider the acceleration of gravity to be 10 m/s2 .

Respuesta :

Part 1: V = gt = 10(11) = 110 m/s Part 2: Vavg = V/2 = 110/2 = 55 m/s Part 3: d = Vavg(t) = 55(11) = 605 m