Answer:
68.4 m
Explanation:
We are given;
Height; y_o = 20 m
Speed; u = 44 m/s
Time; t = 2 s
To solve this, let's first of all find the position of the camera at a time of seconds after its release.
We will use one of Newton's equation of motion;
y(2) - y_o = ut - ½gt²
Negative sign is used on the right hand side because motion is against gravity.
Thus;
y(2) = y_o + ut - ½gt²
y(2) = 20 + (44 × 2) - ((1/2)(9.8)(2²))
y(2) = 88.4 m
Therefore displacement after 2 seconds will be;
y = 88.4 - 20
y = 68.4 m
