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i. Write the dissolution reaction of BaF2, including all states. (0.5 points)
BaF2←>Ba2+(aq)+2F-(aq)

ii. Write the expression for Ksp for BaF2. (0.5 points)

iii. Write the Ksp expression as an algebraic equation, using the variable x to represent concentrations. (1 point)

iv. Find the solubility of BaF2 by solving the equation you wrote in part iii. (0.5 points)

Respuesta :

pstnonsonjoku

Answer:

See Explanation

Explanation:

i) The equation of the dissolution of BF2 is;

BaF2(s)⇄Ba2+(aq)+2F-(aq)

ii) Ksp =[Ba2+]  [2F-]^2

iii) Let the concentration/solubility of [Ba2+] and [2F-] be x

Ksp = [x] [2x]^2

Ksp = 4x^3

iv) x =∛Ksp/4

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