Answer:
889.4 g of Al are produced in the decomposition of 444.71 g of Al₂O₃
Explanation:
This is the reaction of decomposition:
2Al₂O₃ → 4Al + 3O₂
2 moles of aluminum oxide decompose to 4 moles of Al and 3 moles and oxygen.
We convert the mass to moles:
444.71 g . 1mol /26.98g = 16.48 moles.
Now, we can apply the rule of three:
2 moles of Al₂O₃ decompose to 4 moles of Al
Then, 16.48 moles of Al₂O₃ may decompose to (16.48 . 4) /2 = 32.9 moles.
We convert the moles to mass:
32.9 mol . 26.98 g/ mol = 889.4 g
