Respuesta :

crisforp
1)
log 98 = log( 7 * 14 ) = log 7+ log 14= h  +  j ;

2) 
log 175 = log ( 5^2 * 7 ) = log 5 ^ 2 + log 7 = 2 * log 5 + log 7 = 2i + h ;

3)
log 2 = log ( 14 / 7 ) = log 14 - log 7 = j  -  h ;

4)
log 245 = log ( 7^2 * 5 ) = log 7 ^2 + log 5 = 2 * log 7 + log 5 = 2h + i ;
konrad509
[tex]\log98=\log(7\cdot14)=\log 7+\log14=h+j\\\\ \log175=\log(5^2\cdot7)=\log5^2+\log7=2\log5+h=2i+h\\\\ \log2=\log\dfrac{14}{7}=\log14-\log7=j-h\\\\ \log245=\log(5\cdot7^2)=\log5+\log7^2=i+2\log7=i+2h[/tex]

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