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The pressure of a sample of helium in a 200. ml container is 2.0 atm. If the helium is compressed to a pressure of 40. atm without changing the temperature, what would be the new volume of the gas

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sebassandin

Answer:

[tex]V_2=10mL[/tex]

Explanation:

Hello there!

In this case, according to the given information, it will be possible for us to solve this problem by using the Boyle's law as an inversely proportional relationship between pressure and volume:

[tex]P_2V_2=P_1V_1[/tex]

In such a way, we solve for the final volume, V2, and plug in the initial volume and pressure and final pressure to obtain:

[tex]V_2=\frac{P_1V_1}{P_2} \\\\V_2=\frac{2.0atm*200.mL}{40.atm}\\\\V_2=10mL[/tex]

Regards!

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