quirkss
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PLEASE!!! I JUST REALLY NEED HELP RIGHT NOW! T∆T
Using the 45o -45o -90o triangle theorem, solve this triangle.​

PLEASE I JUST REALLY NEED HELP RIGHT NOW TTUsing the 45o 45o 90o triangle theorem solve this triangle class=

Respuesta :

Answer:

Step-by-step explanation:

take 45 degree as reference angle

using sin rule

sin 45 =opposite /hypotenuse

1/[tex]\sqrt{2}[/tex]=24/k(do cross multiplication)

24[tex]\sqrt{2}[/tex]=k