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Question 2 of 10 What is the length of side s of the square shown below? 45 6 09 90° O A. 6 O B. 2 O C. 32 O D. 5 O E. 3 OF. 6-12​

Question 2 of 10 What is the length of side s of the square shown below 45 6 09 90 O A 6 O B 2 O C 32 O D 5 O E 3 OF 612 class=

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Answer:

C

Step-by-step explanation:

Using the cosine ratio in the right triangle and the exact value

cos45° = [tex]\frac{\sqrt{2} }{2}[/tex] , then

cos45° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{s}{6}[/tex] = [tex]\frac{\sqrt{2} }{2}[/tex] ( cross- multiply )

2s = 6[tex]\sqrt{2}[/tex]  ( divide both sides by 2 )

s = 3[tex]\sqrt{2}[/tex] → C

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