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Consider triangle ABC where AB=X+5, BC=X-2, area is 30cm squared. Find X by solving X^2+3X-70=0, and find the perimeter.

Respuesta :

enika

Answer:

What the hell AC is not given so you can't find the Perimeter

Step-by-step explanation:

  • x^2+3x-70=0
  • (x-7)(x+10)=0
  • x-7=0

       x+10=0

  • x=7

       x=-10

AB=x+5

  • AB=12

        AB=-5

BC=x-2

  • BC=5

        BC=-12

Area of ABC = 30cm2

Perimeter of ABC = AB+BC+AC

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