Respuesta :

lalaladidi

Step-by-step explanation:

(3x-2/x)^10

(r+1)th term = 10Cr (3x)^10-r (-2/x)^r

= 10Cr (3)^10-r (-2)^r (x)^10-2r

Let 10-2r = 12

- 2r = 2

r= - 1

The coefficient of x^12

= 10C-1 (3)^11 (-2)^-1

= 10C11 (3)^12 (-1/2)

= (1/11) (3)^12 (-1/2)

= - 1/22 × (3)^12

, end="") y += 5(a) $$$$$(b) $$(c) $$$$$$$$$$$$$$$(d) Nothing wil
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