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We can repeat the derivative operation: the second derivative $f''$ is the derivative of $f'$, the third derivative $f'''$ is the derivative of $f''$, and so on. Find a function $f$ such that $f'$ and $f''$ are not the function 0, but $f'''$ is the constant function 0.

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sqdancefan

Answer:

  f(x) = x^2

Step-by-step explanation:

Any quadratic (2nd-degree) function will have 0 as its third derivative.

  f(x) = ax² +bx +c

  f'(x) = 2ax +b

  f''(x) = 2a

  f'''(x) = 0

Perhaps the simplest such function is f(x) = x^2.

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