select the best explanation for why methanol, ch3oh, cannot be used as a solvent for the deprotonation of a terminal alkyne by sodium amide, nanh2.

Respuesta :

Answer:

d. Methanol is more acidic than the alkyne and will be deprotonated instead.

Explanation:

because acidity is the ability to lose H+, leaving an anion behind; acidity depends on the stability of the anion.