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Using Boyle’s Law, calculate the new volume of the weather balloon at a higher altitude. Assume the volume of the balloon at ground level is 10.0 m3 where the atmospheric pressure is 1.00 atm. What will be its new volume at an altitude of 15 km where the atmospheric pressure is 0.350 atm?

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jcherry99

Answer:

Explanation:

V1 = 10 m^3

P1 = 1.00 atmospheres

V2 = ?

P2 = 0.35

Formula

V1 * P1 = V2 * P2

Solution

10 * 1 = x * 0.35           Combine the left and divide both sides by 0.35

10/0.35 = x

x = 28.57 m^3

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