Respuesta :

ThαtButtєřflíєs

  • Force, F = 15 N
  • Mass,m = 3 kg
  • Time taken, t = 5 sec
  • (v-u) =?

As we know –

[tex]\qquad[/tex][tex] \purple{\bf \twoheadrightarrow F = m a } [/tex]

[tex]\qquad[/tex][tex] \bf \twoheadrightarrow F = m \dfrac{ v-u}{t} [/tex]

[tex]\qquad[/tex][tex] \sf \twoheadrightarrow 15 = 3 \times \dfrac{v-u}{5} [/tex]

[tex]\qquad[/tex][tex] \sf \twoheadrightarrow 3 \times \dfrac{v-u}{5} = 15 [/tex]

[tex]\qquad[/tex][tex] \sf \twoheadrightarrow \dfrac{3}{5} \times (v-u) = 15 [/tex]

[tex]\qquad[/tex][tex] \sf \twoheadrightarrow (v-u)= 15 \times \dfrac{5}{3} [/tex]

[tex]\qquad[/tex][tex] \sf \twoheadrightarrow (v-u)= \cancel{15} \times \dfrac{5}{\cancel{3}}[/tex]

[tex]\qquad[/tex][tex] \sf \twoheadrightarrow v-u = 5 \times 5 [/tex]

[tex]\qquad[/tex][tex] \purple{\bf \twoheadrightarrow v-u = 25 } [/tex]

  • Henceforth, the change in the speed of the body is 25 m/s.

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