The distance of foci = c
Then,
c = 6
To this question, a = 8
As a^2 = b^2 + c^2
Then us will have:
8^2 = 6^2 + c^2
64 = 36 + c^2
64 - 36 = c^2
c^2 = 28
c = √(28)
c = √(7×4)
c = 2√(7)
The equation to this question is:
y^2 / a^2 + x^2/b^2 = 1
Then,
y^2/ 64 + x^2/36 = 1
