Answer:
Let us solve this
We’ll do it by the elementary method
Suppose the original fraction be x/y
Given, x : y = 2:3 ……(i)
then y = 3/2x
Now , by condition,
(x-6)/y = 2/3 * x/y
=> (x-6)/y = 4/9 [ from (i) ]
=> x-6 = 4/9y = (4/9)(3/2)x = 2/3x
=> 3x-18 = 2x [cross multiplication]
=> x = 18
Your Answer: the numerator of the original fraction is = 18
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