Respuesta :
Using the t-distribution, the correct option regarding the test statistic and the p-value is given as follows:
t = –1.85; the P-value is between 0.025 and 0.05.
What are the hypothesis tested?
The null hypothesis is:
[tex]H_0: \mu = 25[/tex]
The alternative hypothesis is:
[tex]H_1: \mu < 25[/tex]
What are the test statistic and the p-value?
The test statistic is given by:
[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]
The parameters are:
- [tex]\overline{x}[/tex] is the sample mean.
- [tex]\mu[/tex] is the value tested at the null hypothesis.
- s is the standard deviation of the sample.
- n is the sample size.
In this problem, the values of the parameters are given as follows:
[tex]\overline{x} = 23.5, \mu = 25, s = 4.8, n = 35[/tex]
Hence the value of the test statistic is:
[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]
[tex]t = \frac{23.5 - 25}{\frac{4.8}{\sqrt{35}}}[/tex]
t = -1.85.
Using a t-distribution calculator, with a left-tailed test, as we are testing if the mean is less than a value and 35 - 1 = 34 df, the p-value is of 0.0365.
Hence the correct statement is:
t = –1.85; the P-value is between 0.025 and 0.05.
More can be learned about the t-distribution at https://brainly.com/question/16194574
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