Respuesta :

konrad509
[tex]\tan 61=\dfrac{y}{10}\\ y=10\tan 61\\\\ \cos 55=\dfrac{z}{10 \tan 61}\\ z=10\tan 61\cos 55\\\\ \sin x=\dfrac{10\tan 61\cos 55}{12}\\ \sin x\approx\dfrac{10\cdot1.8\cdot0.57}{12}\\ \sin x\approx0.855\\ x\approx58.76^{\circ}[/tex]

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