Given:
Radius of the cirle = 11 ft
Angle = 150 degrees
π = 3.14
Let's find the area of the sector of the cicle.
To find the area of the sector, apply the formula:
[tex]A=\frac{\theta}{360}\times\pi r^2\text{ }[/tex]
Where:
π = 3.13
θ = 150 degrees
r = 11
Thus, we have:
[tex]\begin{gathered} A=\frac{150}{360}\times3.14\times11^2 \\ \\ A=\frac{150}{360}\times3.14\times121 \end{gathered}[/tex]
Solving further:
[tex]\begin{gathered} A=0.41667\times3.14\times121 \\ \\ A=158.3ft^2 \end{gathered}[/tex]
Therefore, the sector area of the circle is 158.3 square feet.
ANSWER:
158.3 square feet.
