Solution
We are given 6 numbers, we want to find how many four digits different number that can be formed
Note: All the six numbers are available to occupy the first space of the 4 digit number. There would just be 5 numbers availabe for the second space and 4 numbers for the third and 3 for the last.
Therefore, the number of different combinations is
[tex]6\times5\times4\times3=360[/tex]The answer is
[tex]360[/tex]
