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C. O 32.44 m/sD. O 24.45 m/sE. O 3.293 m/s6. A certain spring extends by 0.4 m when an objectof mass 0.9 kg hangs from it. Calculatethe Hook's constant of the spring. (1 point)A. O13.416 N/mB. O 33.766 N/mC. 38.169 N/mD. O 22.05 N/mE. O8.241 N/m

C O 3244 msD O 2445 msE O 3293 ms6 A certain spring extends by 04 m when an objectof mass 09 kg hangs from it Calculatethe Hooks constant of the spring 1 pointA class=

Respuesta :

Given,

The mass of the object is

[tex]m=0.9\text{ kg}[/tex]

The length of the spring is

[tex]x=0.4\text{ m}[/tex]

To find: Calculate the Hook's constant.

Solution:

Hook's law is given as

[tex]F=kx[/tex]

Now,

[tex]\begin{gathered} k=\frac{mg}{x} \\ k=\frac{0.9\times9.8}{0.4} \\ k=22.05\text{ N/m} \end{gathered}[/tex]

Hence, the given option (d) is correct.

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