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As Long, As Wide
The length of a rectangular sign is 3 times its width. If the sign's perimeter is 32 inches, what is
the sign's area? »
Solve on paper. Then check your answer on Zearn. »
The sign's area is square inches.
.

Respuesta :

Answer:

The area of the rectangular sign is 48 squared inches

Explanation:

Here, given the perimeter of the rectangle and the relationship between the length and width, we want to get the area of the rectangle

Let the length be represented as l with the width represented as w

From the question, we have it that the length is 3 times the width

Thus:

[tex]l\text{ = 3}\times\text{ w = 3w}[/tex]

Mathematically, the perimeter can be calculated as:

[tex]P\text{ = 2(l + w)}[/tex]

So, we have it that:

[tex]\begin{gathered} 32\text{ = 2(w + 3w)} \\ 8w\text{ = 32} \\ w\text{ = }\frac{32}{8} \\ w\text{ = 4 inches} \end{gathered}[/tex]

Now, we can get the length

It was stated that the length is 3 times the width

we have it that:

[tex]l\text{ = 3w = 3}\times4\text{ = 12 inches}[/tex]

Mathematically, the area of rectangle is the product of the width and length of the rectangle as stated below:

[tex]\begin{gathered} \text{Area = length }\times\text{ width} \\ \text{Area = 12}\times\text{ 4 = 48 squared inches} \end{gathered}[/tex]