Given,
The length of the vector, V=25 units.
The angle of the vector, θ=53.1°
The x-component of the vector is given by,
[tex]V_x=V\cos \theta[/tex]On substituting the known values,
[tex]\begin{gathered} V_x=25\times\cos 53.1^{\circ} \\ =15.01\text{ units} \\ \approx15\text{ units} \end{gathered}[/tex]The y-component of the vector is given by,
[tex]V_y=V\sin \theta[/tex]On substituting the known values,
[tex]\begin{gathered} V_y=25\times\sin 53.1^{\circ} \\ =19.99\text{ units} \\ \approx20\text{ units} \end{gathered}[/tex]Thus, the x-component of the vector is 15 units and the y-component of the vector is 20 units.
