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Write the equation of the circle with center (5,1) and a point on the circle at (8,-2). a) (x – 5)2 + (y – 1)2 = square root 18b) (x - 5)2 + (1 - 1)2 = 18 c) (x – 8)2 + (y + 2)2 = 18d) (x + 5)2 + ( + 1)2 = 18

Respuesta :

The general equation of circle ,

[tex](x-x_1)^2+(y-y_1)^2=r^2[/tex]

The centre is

[tex](x_1,y_1_{}_{})[/tex]

The radius is r.

The distance between two points the centre and the point on the circle gives radius.

[tex]r=\sqrt[]{(8-5)^2}+(-2-1)^2[/tex][tex]r=\sqrt[]{9+9}[/tex][tex]r^2=18[/tex]

The equation of cirlce formed is,

[tex](x-5)^2+(y-1)^2=18[/tex]

The correct option is b.

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