Solution:
Given:
[tex]\begin{gathered} base\text{ area, }A=17ft^2 \\ height,h=8ft \end{gathered}[/tex]
The solid is a triangular pyramid.
The volume of a pyramid is given by;
[tex]\begin{gathered} V=\frac{1}{3}\times base\text{ area}\times height \\ V=\frac{1}{3}Ah \end{gathered}[/tex]
Hence,
[tex]\begin{gathered} V=\frac{1}{3}\times17\times8 \\ V=\frac{136}{3} \\ V=45.33 \\ \\ To\text{ the nearest foot,} \\ V=45ft \end{gathered}[/tex]
Therefore, the volume of the triangular pyramid to the nearest foot is 45 feet.
