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A rectangle has a length of 10 feet and a width of 13 feet.a) Given P = 2L + 2W, what is the perimeter of the rectangle?b) Given A = L•W, what is the area of the rectangle?a) The perimeter of the rectangle isfeet. (Type an integer.)b) The area of the rectangle issquare feet. (Type an integer.)

Respuesta :

Answer:

a) The perimeter of the rectangle is 46 feet.

b) The area of the rectangle is 130 square feet

Explanation:

L represents the length of the rectangle and W represents the width of the rectangle.

So, to find the perimeter of the rectangle, we need to replace L by 10 ft and W by 13 ft as:

P = 2L + 2W

P = 2(10) + 2(13)

P = 20 + 26

P = 46

Then, the perimeter of the rectangle is 46 feet.

In the same way, the area of the rectangle can be calculated as:

A = L·W

A = 10·13

A = 130

Then, the area of the rectangle is 130 square feet.

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