Given,
The force exerted, F=100 N
The mass of the safe, m=50 kg
From Newton's second law, the force applied on an object is equal to the product of the mass of the object and the acceleration produced due to the applied force.
Therefore,
[tex]F=ma[/tex]Where a is the acceleration,
On substituting the known values,
[tex]\begin{gathered} 100=50a \\ \Rightarrow a=\frac{100}{50} \\ =2m/s^2 \end{gathered}[/tex]Thus the acceleration of the safe is 2 m/s²
