SOLUTION
The probability that you use the freight elevator exactly four times is,
[tex]P=^7C_4(\frac{1}{4})^4(\frac{3}{4})^3[/tex]Simplify
[tex]\begin{gathered} P=\frac{7\times6\times5\times4\times3!}{(7-4)!4!}(\frac{1}{4})^4(\frac{3}{4})^3 \\ P=\frac{7\times6\times5\times4\times3!}{3!4!}(\frac{1}{4})^4(\frac{3}{4})^3=35(\frac{1}{4})^4(\frac{3}{4})^3=\frac{945}{16384} \end{gathered}[/tex]Hence, the answer is
[tex]\frac{945}{16384}[/tex]