Respuesta :

We know that the perimeter is 22 inches.

Also, the length is one inch less than two times the width, which means

[tex]l=2w-1[/tex]

Then, we use the perimeter formula

[tex]\begin{gathered} P=2(w+l) \\ 22=2(w+2w-1) \\ \frac{22}{2}=3w-1 \\ 11=3w-1 \\ 3w=11+1 \\ w=\frac{12}{3} \\ w=4 \end{gathered}[/tex]

Then, we find the length

[tex]l=2\cdot4-1=8-1=7[/tex]

Hence, the dimensions are 4 inches wide and 7 inches long.

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