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the pressure of a sample of argon gas was increased from 2.32 atm2.32 atm to 7.16 atm7.16 atm at constant temperature. if the final volume of the argon sample was 18.3 l,18.3 l, what was the initial volume of the argon sample? assume ideal behavior.

Respuesta :

initial volume of the argon sample = 5.93L according to Boyle's law

What is Boyle's law ?

Boyle's law, also known as Mariotte's law, is a relationship describing how a gas will compress and expand at a constant temperature. The pressure (p) of a given quantity of gas changes inversely with its volume (v) at constant temperature, according to this empirical connection, which was established by the physicist Robert Boyle in 1662. In equation form, this means that pv = k, a constant.

According to Boyle's law

P1/V1 = P2/V2

P1 = initial pressure

P2 = final pressure

V1 =initial volume

V2= final volume

V1 = P1*V2/P2

V1 = 2.32*18.3/7.16 = 5.93L

initial volume of the argon sample = 5.93L according to Boyle's law

To know about Boyle's law from the link

https://brainly.com/question/26040104

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