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When given a question such as…“During an experiment, an object is placed on a disk that rotates about an axle through its center, as shown in Figure 1. The disk is a distance R =0.10  m from the center and rotates with a constant tangential speed of 0.60 ms. A free body diagram of the forces exerted on the block is shown in Figure 2 with an unknown force of friction. What is the force of friction exerted on the object?“How do I know what formula to use to plug in my values to?

Respuesta :

ANSWER:

0.72 N

STEP-BY-STEP EXPLANATION:

Due to the rotation, the centrifugal force is also worked in the outward direction.

Then the friction force is equal to:

[tex]F_C=\frac{mv^2}{r}[/tex]

We calculate the mass, like this.

[tex]\begin{gathered} F=m\cdot g \\ m=\frac{F}{g}=\frac{2}{9.81} \\ m=0.2\text{ kg} \end{gathered}[/tex]

Replacing:

[tex]\begin{gathered} F_C=\frac{0.2\cdot0.6^2}{0.1} \\ F_C=0.72\text{ N} \end{gathered}[/tex]

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