Given:
A right square pyramid has a base edge length of 10 centimetres.
The height is 12 centimetres.
The surface area of the square pyramid is,
[tex]\begin{gathered} A=a^2+2a\sqrt[]{\frac{a^2}{4}+h^2} \\ a=10,h=12 \\ SA=10^2+2(10)\sqrt[]{\frac{10^2}{4}+12^2} \\ SA=100+20\sqrt[]{169} \\ SA=100+20(13) \\ SA=100+260 \\ SA=360\text{ square cm} \end{gathered}[/tex]Answer: surface area of the pyramid is 360 square cm.
