If the lines in problem below, have a resistance of 100-Ω, calculate the change of voltage along each line. We are asked to determine the current given the power and the voltage. To do that we will use the following formula:P=IVWhere:P= powerI= currentV= voltageNow, we divide both sides by "V":PV=INow, we convert the power from "kW" to "W" using the following conversion factor:1kW=1000WMultiplying by the conversion factor we get:200kW×1000W1kW=200000WNow, we plug in the values in the formula:200000W48000V=ISolving the operations:4.2A=ITherefore, the current is 4.2 Amp.

Based on the information of the last point, we know the current and now we have the resistance. With these two numbers we can calculate the drop of voltage generated by the resistance.

Is important to highlight that we asume the same current for each line because the current is constant in all the parallel lines.

[tex]\begin{gathered} V=IR \\ V=100\Omega\cdot4.2A \\ V=420V \end{gathered}[/tex]