Let the age of the father is x and the age of the son is y
The father is currently 4 times as old as his son
So,
[tex]x=4y[/tex]Two years ago, he was 5 times as old as his son
So,
[tex](x-2)=5(y-2)[/tex]by substitute from (x = 4y) in the last equation:
[tex]\begin{gathered} 4y-2=5(y-2) \\ 4y-2=5y-10 \\ 10-2=5y-4y \\ 8=y \end{gathered}[/tex]so, the age of the son = 8
So, the age of the father = 4 * 8 = 32
The answer is option d. 32
