1) The zeros of the function are 1, 3, 4
Explanation:1) y= (x-1)(x²-7x+12)
To find the zeros of the function above, we need to factorise the quadratic function and equate the factors to zero.
(x - 1) = 0 or (x²-7x+12) = 0
(x - 1) = 0
x - 1 = 0
x = 1
factorising (x²-7x+12):
(x²-7x+12) = 0
Factos of 12 whose sum gives -7 are -3 and - 4
x² - 3x - 4x + 12 = 0
x(x - 3) -4(x - 3) = 0
(x - 4)(x - 3) = 0
(x - 4) = 0 or (x - 3) = 0
x = 4 or x = 3
The zeros of the function are 1, 3, 4
