Given
tangent function , vertical stretch of 2, period of π/2.
Find
equation for this trigonometric function
Explanation
as we know the standard form of the tangent function is given by
[tex]y=a\tan(bx+c)d[/tex]here vertival stretch of 2
a = 2
period = pi/2=pi/b
so , b= 2
so , y = 2tan(2x+0)+0
Final Answer
Therefore, the equation for this trigonometric function is y = 2tan(2x+0)+0 or y = 2tan(2x)
