TannahT635568 TannahT635568

28-10-2022
Mathematics

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Given line l is a perpendicular bisector of ⎯⎯⎯⎯⎯⎯⎯⎯CB¯ and AB = x + 7.5 and AC = 3x - 10.9 find x. (Round to the nearest tenth)

Given line l is a perpendicular bisector of CB and AB x 75 and AC 3x 109 find x Round to the nearest tenth class=

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KaylibV374107 KaylibV374107

28-10-2022

If line l is a perpendicular bisector of by the converse of the perpendicular bisector theorem.

Then,

AB = AC

Replacing

x+7.5 =3x-10.9

Solve for x

7.5+10.9 = -x+3x

18.4 = 2x

Change sides

2x = 18.4

x= 18.4/2

x = 9.2

Hence, the correct answer is x=9.2

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