Given the combined inequality as;
[tex]2<4x+10\leq14[/tex]
Then, we can break the combined inequality to two separate inequalities as;
[tex]\begin{gathered} 2<4x+10 \\ \text{and} \\ 4x+10\leq14 \end{gathered}[/tex]
From the first inequality, we have;
[tex]\begin{gathered} 2<4x+10 \\ 2-10<4x \\ -8<4x \\ -\frac{8}{4}<\frac{4x}{4} \\ -2-2 \end{gathered}[/tex]
On a number line, the solution to the first inequality is;
The arrow shows that the numbers to the right side are greater than -2.
Also, from second inequality, we have;
[tex]\begin{gathered} 4x+10\leq14 \\ 4x\leq14-10 \\ 4x\leq4 \\ \frac{4x}{4}\leq\frac{4}{4} \\ x\leq1 \end{gathered}[/tex]
The solution of the second inequality on the number line is;
The graph shows the numbers that are less than or equal to 1.
Hence, the combined solution of the given inequality is;
[tex]-2and its graph is;
