The vertex of the curve iis given to be
[tex](5,-6)[/tex]
The vertex form of a quadratic equation is given as
[tex]y=a(x-h)^2+k[/tex]
Where (h, k) is the vertex
From the given vertex, we have that
h = 5, k = -6
Therefore, the equation becomes
[tex]y=a(x-5)^2-6[/tex]
whcere a can be any value
When a = 1
The graph will be
[tex]y=(x-5)^2-6[/tex]
