Solution:
From the question, we gathered that;
Using sine trigonometry ratio;
[tex]\begin{gathered} \sin\theta=\frac{opposite}{hypotenuse} \\ \\ \theta=79^o,hypotenuse=x,opposite=80 \\ \end{gathered}[/tex]
Thus;
[tex]\begin{gathered} \sin79^o=\frac{80}{x} \\ \\ x=\frac{80}{\sin79^o} \\ \\ x=81.5m \end{gathered}[/tex]
ANSWER: The wire is 81.5 meters long.
