Respuesta :
Answer:
The temperature of the gas is 8.28 °C.
Explanation:
The given information from the exercise is:
- Number of moles (n): 0.6500 moles
- Volume (V): 1.00L
- Pressure (P): 15.0atm
With the Ideal Gases Law formula, we can calculate the temperature of the gas, by replacing the values of n, V and P:
[tex]\begin{gathered} P*V=n*R*T \\ 15.0atm*1.00L=0.6500mol*0.082\frac{atm*L}{mol*K}*T \\ 15.0atm*L=0.0533\frac{atm*L}{K}*T \\ \frac{15.0atm*L}{0.0533\frac{atm*L}{K}}=T \\ 281.43K=T \end{gathered}[/tex]Finally, we have to convert 281.43K to °C:
281.43 - 273.15 = 8.28°C
So, the temperature of the gas is 8.28 °C.
