Respuesta :

[tex]\begin{gathered} \text{Area of any triangle , A= }\frac{1}{2}bh\text{ } \\ \text{where b = base, h=height} \\ h=6in \\ \text{base = b, Area = A} \\ A=\frac{1}{2}\text{ x b x 6} \\ A=\frac{6b}{2} \\ 2A=6b \\ 6b=2A \\ b=\frac{2A}{6} \\ b=\text{ }\frac{A}{3} \end{gathered}[/tex]

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