Let us statrt to solve this equation
[tex]x^3=-65[/tex]To find the value of x take cube root for both sides
[tex]\sqrt[3]{x^3}=\sqrt[3]{-65}[/tex]The cube root will cancel the index of x, so
[tex]x=\sqrt[3]{-65}[/tex]You can leave the answer with exact for or change it to decimal
