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Calculate the ΔH for the reaction 4 CO2 (g) + 2 H2O (g) → 2 C2H2 (g) +5 O2 (g), from the following:C2H2 (g) + 2 H2 (g) → C2H6 (g)ΔH = – 94.5 kJH2O (g) → H2 (g) + ½ O2 (g)ΔH = + 241.8 kJC2H6 (g) + 3 ½ O2 (g) → 2 CO2 (g) + 3 H2O (g)ΔH = – 283 kJ

Calculate the ΔH for the reaction 4 CO2 g 2 H2O g 2 C2H2 g 5 O2 g from the followingC2H2 g 2 H2 g C2H6 gΔH 945 kJH2O g H2 g O2 gΔH 2418 kJC2H6 g 3 O2 g 2 CO2 g class=

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Answer:

Explanation:

Here, we want to calculate the change in enthalpy of the given reaction

To get that, we are going to use the 3 related equations below it

We proceed as follows:

[tex]\begin{gathered} We\text{ multiply equation ii by 3} \\ The\text{ heat becomes } \\ 3\text{ }\times\text{ 241.8 = +725.4 KJ} \end{gathered}[/tex]

We arrange equation 1 in the opposite direction

This makes the heat become:

[tex]+94.5\text{ KJ}[/tex]

For equation iii, we arrange in opposite direction too

The heat becomes:

[tex]-725.4\text{ KJ}[/tex]

We can now begin to make additions and subtractions as follows:

[tex]undefined[/tex]

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