Given the following System of equation:
[tex]\begin{cases}y=8-x \\ 4x-3y=-3\end{cases}[/tex]
You can solve it using the Substitution method. The steps are shown below:
1. You can substitute the first equation into the second equation:
[tex]\begin{gathered} 4x-3y=-3 \\ 4x-3(8-x)=-3 \end{gathered}[/tex]
2. Now you have to solve for the variable "x":
[tex]\begin{gathered} 4x-24+3x=-3 \\ 7x=-3+24 \\ \\ x=\frac{21}{7} \\ \\ x=3 \end{gathered}[/tex]
3. Finally, substitute the value of "x" into the first equation and evaluate, in order to find the value of "y". Then:
[tex]\begin{gathered} y=8-x \\ y=8-(3) \\ y=5 \end{gathered}[/tex]
You can write the solution in this form:
[tex](3,5)[/tex]
The answer is: Option C.
