The given expression :
[tex]\frac{2}{3}\times\frac{?}{5}=\frac{14}{15}[/tex]Let the missing term is x
[tex]\frac{2}{3}\times\frac{x}{5}=\frac{14}{15}[/tex]Simplify :
[tex]\begin{gathered} \frac{2x}{3\times5}=\frac{14}{15} \\ \frac{2x}{15}=\frac{14}{15} \\ \text{Apply cross multiplication:} \\ 2x=\frac{14}{15}\times15 \\ 2x=14 \\ x=\frac{14}{2} \\ x=7 \end{gathered}[/tex]So, x = 7
Missing Numerator is 7
Answer : Missing Numerator is 7
