Solution
Given the system of the equations shown below:
[tex]\begin{gathered} y-2x=-2 \\ y-x=1 \end{gathered}[/tex]
I will solve your system by substitution.
(You can also solve this system by elimination.)
[tex]\begin{gathered} y-2x=-2.......(1) \\ \frac{y-x=\text{ }1}{-x=-3}........(2)\text{ subtract equ\lparen2\rparen from equ\lparen1\rparen} \\ x=3 \end{gathered}[/tex]
Substitute the value of x in equ(1)
[tex]\begin{gathered} y-2x=-2 \\ y-2(3)=-2 \\ y-6=-2 \\ y=-2+6 \\ y=4 \end{gathered}[/tex]
Therefore the value of x = 3, y = 4
Correct answer = Option A
